Tricky Math Problem
May 17, 2020 14:44:35 #
May 17, 2020 14:45:11 #
jerryc41 wrote:
The math isn't difficult. You just have to observe and think.
Revised answer = 92
May 17, 2020 14:51:17 #
scooter1
Loc: Yacolt, Wa.
jerryc41 wrote:
The math isn't difficult. You just have to observe and think.
100
May 17, 2020 15:02:36 #
May 17, 2020 15:03:42 #
May 17, 2020 15:11:40 #
David Martin
Loc: Cary, NC
43
i.e., 5 + [5+10+4] x 2 = 5 + 19 x 2 = 5 + 38 = 43
where [5+10+4] = boy wearing 2 shoes and holding 2 bouquets
i.e., 5 + [5+10+4] x 2 = 5 + 19 x 2 = 5 + 38 = 43
where [5+10+4] = boy wearing 2 shoes and holding 2 bouquets
May 17, 2020 15:12:06 #
May 17, 2020 15:12:55 #
May 17, 2020 15:12:57 #
May 17, 2020 15:20:27 #
Old Coot wrote:
Nope. 2 shoes = 10, so 1 shoe = 5shoe =10
boy =5
cone= 4
10+5=15. x4= 60
boy =5
cone= 4
10+5=15. x4= 60
2 cones = 4, so 1 cone = 2
boy with 2 cones and 2 shoes = 5 + 4 + 10 = 19
(2 x 19) + 5 = 43
May 17, 2020 15:23:03 #
May 17, 2020 15:27:33 #
May 17, 2020 15:33:35 #
May 17, 2020 15:55:26 #
May 17, 2020 15:55:33 #
traveler90712 wrote:
Rule of order
This means that you should do what is possible within parentheses first, then exponents, then multiplication and division (from left to right), and then addition and subtraction (from left to right).
5+(19*2)=43
This means that you should do what is possible within parentheses first, then exponents, then multiplication and division (from left to right), and then addition and subtraction (from left to right).
5+(19*2)=43
Yes, remember "Please excuse my dear aunt sally."
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