Tricky Math Problem
May 16, 2020 07:04:14 #
May 16, 2020 07:13:04 #
May 16, 2020 07:13:09 #
May 16, 2020 07:14:42 #
May 16, 2020 07:16:07 #
May 16, 2020 07:16:19 #
May 16, 2020 07:23:46 #
OK, I changed my mind. Here is what I come up with:
2 shoes = 10 therefore 1 shoe =5
Boy = 5
2 bouquets = 4 therefore 1 bouquet = 2
Final formula is:
1 shoe + (boy holding 2 bouquets and wearing 2 shoes) X 1 bouquet which would numerically be 5 + (5+4+10) X 2 or 5+19X2. Using the MDAS method of solving that would then be 5+38=43 (final answer).
2 shoes = 10 therefore 1 shoe =5
Boy = 5
2 bouquets = 4 therefore 1 bouquet = 2
Final formula is:
1 shoe + (boy holding 2 bouquets and wearing 2 shoes) X 1 bouquet which would numerically be 5 + (5+4+10) X 2 or 5+19X2. Using the MDAS method of solving that would then be 5+38=43 (final answer).
May 16, 2020 07:23:50 #
Depends if you do the multiplication first or last. First I get 43, last I get 48,
May 16, 2020 07:33:19 #
May 16, 2020 07:37:13 #
jerryc41 wrote:
The math isn't difficult. You just have to observe and think.
30
5X4=20
20+10=30
May 16, 2020 07:39:27 #
May 16, 2020 07:40:58 #
28 (5 + 9 )x 2 or
is it
23 5+ (9 x 2)
you really need parentheses is this equation
is it
23 5+ (9 x 2)
you really need parentheses is this equation
May 16, 2020 07:41:49 #
aphelps
Loc: Central Ohio
jerryc41 wrote:
The math isn't difficult. You just have to observe and think.
5+5+2=12
May 16, 2020 07:45:31 #
May 16, 2020 07:45:38 #
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