Tricky Math Problem
May 17, 2020 11:13:18 #
jerryc41 wrote:
The math isn't difficult. You just have to observe and think.
14?
Oops: 40
May 17, 2020 11:13:40 #
Leo_B
Loc: Houston suburb
In the absence of parenthesis the order of operation is MDAS.
Six shoes = 30 so shoes are 5 each.
Two shoes and 2 boys = 20. Take away the 10 we know the two shoes are worth and 2 boys = 10 so boys are 5 each.
Four cones and one boy = 13. Take away the 5 we know the boy is worth and 4 cones = 8 so cones are 2 each. So you have 19 x 2 = 38 first. Then 5 + 38 = 43. The boy is holding 2 cones and wearing 2 shoes making his total value 19. That is multiplied by the 2 value of one cone. Add the 5 value of one shoe for the answer, 43.
Six shoes = 30 so shoes are 5 each.
Two shoes and 2 boys = 20. Take away the 10 we know the two shoes are worth and 2 boys = 10 so boys are 5 each.
Four cones and one boy = 13. Take away the 5 we know the boy is worth and 4 cones = 8 so cones are 2 each. So you have 19 x 2 = 38 first. Then 5 + 38 = 43. The boy is holding 2 cones and wearing 2 shoes making his total value 19. That is multiplied by the 2 value of one cone. Add the 5 value of one shoe for the answer, 43.
May 17, 2020 11:28:29 #
randave2001 wrote:
OK, I changed my mind. Here is what I come up with:
2 shoes = 10 therefore 1 shoe =5
Boy = 5
2 bouquets = 4 therefore 1 bouquet = 2
Final formula is:
1 shoe + (boy holding 2 bouquets and wearing 2 shoes) X 1 bouquet which would numerically be 5 + (5+4+10) X 2 or 5+19X2. Using the MDAS method of solving that would then be 5+38=43 (final answer).
2 shoes = 10 therefore 1 shoe =5
Boy = 5
2 bouquets = 4 therefore 1 bouquet = 2
Final formula is:
1 shoe + (boy holding 2 bouquets and wearing 2 shoes) X 1 bouquet which would numerically be 5 + (5+4+10) X 2 or 5+19X2. Using the MDAS method of solving that would then be 5+38=43 (final answer).
May 17, 2020 11:32:04 #
Leo_B wrote:
In the absence of parenthesis the order of operati... (show quote)
Interesting that computer spreadsheets will not agree with MDAS. Lack of brackets will regard the multiplier sign as a plus sign. My non-math logic would apply everything from left to right, with the result applied before moving onward.
May 17, 2020 11:35:16 #
Shoes 10 - (10+10+10=30)
Boy 5 - (5+5+10=20)
Cone 4 - (4+4+5=13)
Answer - (10+5=15 x 4=60)
Boy 5 - (5+5+10=20)
Cone 4 - (4+4+5=13)
Answer - (10+5=15 x 4=60)
May 17, 2020 11:37:02 #
May 17, 2020 11:44:32 #
mjc925
Loc: SF Bay Area
48 or 43 depending on if you are using MDAS (which I suppose you should be since no ()'s) so final answer 43.
May 17, 2020 11:59:25 #
May 17, 2020 12:01:01 #
May 17, 2020 12:04:13 #
May 17, 2020 12:23:46 #
fetzler
Loc: North West PA
Shoes =10 2 shoes
Boy =5
Cone =4 two cones
Boy + 2cones =9
5 + (9*2) = 23 using regular operator precedence 1 shoe =5 boy has 2 cones
or
(5+9)*2 = 28
Boy =5
Cone =4 two cones
Boy + 2cones =9
5 + (9*2) = 23 using regular operator precedence 1 shoe =5 boy has 2 cones
or
(5+9)*2 = 28
May 17, 2020 12:39:08 #
JFCoupe
Loc: Kent, Washington
Architect1776 wrote:
30
5X4=20
20+10=30
5X4=20
20+10=30
I agree with this solution. I always was taught that you do exponential operations first, then multiplication and division operations and then addition and subtraction. So I also go with 30 for the solution.
May 17, 2020 12:43:10 #
May 17, 2020 12:55:26 #
May 17, 2020 12:56:35 #
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