1 shoe + (boy holding 2 bouquets and wearing 2 shoes) X 1 bouquet which would numerically be 5 + (5+4+10) X 2 or 5+19X2. Using the MDAS method of solving that would then be 5+38=43 (final answer).
I think we have a winner! Do you get a brand new camera? ;)
BridgesLoc: Memphis, Charleston SC, now Nazareth PA
Architect1776 wrote:
Actually it is 43.
I don't see where it says it should be worked as an algebraic formula by putting the second item in the equation in parentheses. If you use straight math like I did, it comes out 48.
I don't see where it says it should be worked as an algebraic formula by putting the second item in the equation in parentheses. If you use straight math like I did, it comes out 48.
That's the answer I got too. Working it as it a regular math problem.
twosummersLoc: Melbourne Australia or Lincolnshire England
Pair of shoes = 10 Therefore 1 shoe = 5 2 boys = (20-10) = 10, so boy = 5 4 cones = 13-5=8 so cone =2 Therefore boy +2 cones + 2 shoes (19) x 1 cone (2) = 38 then add 1 shoe (5) so answer is 43