6x7 and 8x10 a math problem
Dec 7, 2017 14:21:16 #
It looks like jcboy can do math. After readin the other posts, it appears to be an uncommon ability! JK!
Dec 7, 2017 14:44:55 #
for this to work the ratio of one side to the other would have to be the same. The ration of a 6x7 is 7/6=1.166666. The ratio of an 8x10 is 10/8=1.25. They are not equal. Thus, an even border will not work.
--Bob
--Bob
BebuLamar wrote:
We know that you can't enlarge a 6x7 image to exactly fit an 8x10 frame but..
Suppose that the 6x7 negative contains an image of 60mm x 70mm (which isn't exactly true) and you add equal borders around the image how big should the image be enlarged to in order to exactly fit the 8x10 frame with equal border around it?
Suppose that the 6x7 negative contains an image of 60mm x 70mm (which isn't exactly true) and you add equal borders around the image how big should the image be enlarged to in order to exactly fit the 8x10 frame with equal border around it?
Dec 7, 2017 14:45:36 #
Dec 7, 2017 14:57:36 #
rmalarz wrote:
for this to work the ratio of one side to the other would have to be the same. The ration of a 6x7 is 7/6=1.166666. The ratio of an 8x10 is 10/8=1.25. They are not equal. Thus, an even border will not work.
--Bob
--Bob
Exactly ...
Dec 7, 2017 16:07:50 #
Dec 7, 2017 18:53:21 #
BebuLamar wrote:
We know that you can't enlarge a 6x7 image to exactly fit an 8x10 frame but..
Suppose that the 6x7 negative contains an image of 60mm x 70mm (which isn't exactly true) and you add equal borders around the image how big should the image be enlarged to in order to exactly fit the 8x10 frame with equal border around it?
Suppose that the 6x7 negative contains an image of 60mm x 70mm (which isn't exactly true) and you add equal borders around the image how big should the image be enlarged to in order to exactly fit the 8x10 frame with equal border around it?
The thing that bugs me about this silly post is where does anybody get a 6x7 negative. What camera produces this odd size. None that I know of.
Dec 7, 2017 20:06:12 #
WF2B wrote:
The thing that bugs me about this silly post is where does anybody get a 6x7 negative. What camera produces this odd size. None that I know of.
It's a common size for medium format cameras. Mamiya and Pentax, among others, made them.
Dec 7, 2017 20:08:49 #
daddybear wrote:
solution:
print size to best resolution
custom mat
custom frame
print size to best resolution
custom mat
custom frame
Or just leave a little extra space and use a standard 8x10 frame.
Dec 7, 2017 23:16:46 #
jcboy3 wrote:
It cannot be done.
You want to add an equal border to a 6x7 ratio image to get an 8x10 image. Let K be the width of the border. Then what you want is:
(8-K) / (10-K) = 6 / 7
or
56 - 7K = 60 - 6K
or
K = -4
Which means there is no solution to the problem.
You want to add an equal border to a 6x7 ratio image to get an 8x10 image. Let K be the width of the border. Then what you want is:
(8-K) / (10-K) = 6 / 7
or
56 - 7K = 60 - 6K
or
K = -4
Which means there is no solution to the problem.
6X7=42 8X10=80 Easy
Dec 8, 2017 00:42:47 #
Dec 8, 2017 14:59:31 #
BebuLamar wrote:
We know that you can't enlarge a 6x7 image to exactly fit an 8x10 frame but..
Suppose that the 6x7 negative contains an image of 60mm x 70mm (which isn't exactly true) and you add equal borders around the image how big should the image be enlarged to in order to exactly fit the 8x10 frame with equal border around it?
Suppose that the 6x7 negative contains an image of 60mm x 70mm (which isn't exactly true) and you add equal borders around the image how big should the image be enlarged to in order to exactly fit the 8x10 frame with equal border around it?
As you said, some pictures cannot be enlarged to fit exactly in a particular frame. And equal borders around the image is not always necessary or possible. If you want the picture in an 8x10 frame without borders, you are not going to be able to do it. If you want borders, just print the photo the size you want on the right size paper for the frame. Or print it the size you want and cut a mat.
Brain-teasers are entertaining for some, but when framing photos the only math you need to do is decide on the size of image and paper to go into the frame. And if you want to mat the picture, you print it, cut the outside dimensions of the mat to fit the frame, then calculate the borders needed on each side to cut out the opening with an extra 1/4" on each side for overlap on the photo. They don't have to be even numbers, or the same width all around. They just have to be the same on the top and bottom [unless you want the bottom wider] and the same on the sides.
Keeping it practical, with as little "fuss" as possible, and have it coming out looking good are what matter.
Dec 9, 2017 14:34:44 #
The simplest answer to your math problem is that the solution is derived from a formula using multiplication, not addition. However, I know of one completely coincidental conjunction of addition and multiplication that over the years has been a life (and money) saver to me when framing.
If you make a 6x9 print (35mm proportion), and cut a mat to reveal 1/4" of white printing paper on each side (6-1/2" x 9-1/2" opening), you will have an equal borders in an 11 x 14 inch frame.
If you make a 6x9 print (35mm proportion), and cut a mat to reveal 1/4" of white printing paper on each side (6-1/2" x 9-1/2" opening), you will have an equal borders in an 11 x 14 inch frame.
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