a6k wrote:
Gene, I'm not disputing your statement but I don't quite understand it. The lens on my RX10 when zoomed out, not even to maximum, is F4. As you know, it's a 220 mm lens at maximum zoom (real mm's, not "equivalent").
So why does the size of the sensor affect the diffraction? The size of the aperture is a function of the focal length and the "F stop". Does the light know when it passes the hole how big the sensor is?
I'm just not understanding this.
This may help:
https://www.cambridgeincolour.com/tutorials/diffraction-photography.htmhttps://www.photopills.com/calculators/diffraction#:~:text=Pixel%20size%3A%20The%20size%20of,2.5%20times%20the%20Pixel%20size.
https://en.wikipedia.org/wiki/Airy_diskThe diffraction limit is not a hard limit. Diffraction occurs when the size of the Airy Disk - which is defined as the "best-focused spot of light that a perfect lens with a circular aperture can make", and it is calculated based on F-number of the lens and the wavelength of the light passing through an optical system), is more than 2.5X bigger in diameter than the pixel that is capturing it.
So, while in it's purest form it has nothing to do with the camera, it has everything to do with the camera sensor size, pixel density, etc.
The Cambridge in Color page has a few interactive tools to see how this works, and the advanced option of the Diffraction Limit Calculator takes into consideration print size, viewing distance, eye sight, pixel resolution, aperture and sensor size.
Using the advanced calculator you can see that if you use a 20 mp 1" sensor, and you set the circle of confusion to be based on pixels, F5.6 will be diffraction limited (Airy disk diameter is > circle of confusion diamter), while F4 will be fine, when viewing images on a screen. One can use smaller apertures when viewing prints at "normal" distances, due to the human eye's limit of acuity.
This is pretty thick stuff, but just use the tools and charts and you'll be fine.