notBert Loc: Ft. Collins, Colorado

I have been taking fotos of moon w/ my Sony A6300 & the 200-600 Sony telly. As a starting point for nitely fotos it would be most helpful if i could calculate exposure from data of moon's apparent magnitude published for a specific date & time. The closest i found to this is a calculation of smallest magnitude star visible. The formula is:

(log¹⁰D*5)+7 = minimum visible magnitude. ¹⁰ is base 10log, D is aperture for Sony 200-600 = 9.5cm

and

EV= log²(N²/t) where log² is base 2log, but N² is N*N & t is time.
While i once passed a course in diffyQ at 87 my algebra skills have dropped down a hole in my Swiss cheese brain & i am at a loss to combine these two equations. I would prefer to calculate the shutter speed, t for a given f-stop & ISO. To pick some numbers say, f8.0 at ISO 100 for the Sony 200-600 telly w/ D = 9.5cm.
Or if there are other ways to calculate it please show me how. Trial & error are becoming frustrating as is using spot meter on hilites and dialing in minus exposure compensation.

TIA

rgrenaderphoto Loc: Hollywood, CA

IMHO, you are making this waaaaaaaaaaaaay too complicated.

Use the old standby LOONEY 11 RULE:

The “looney 11 rule” states that for astronomical photos of the Moon’s surface, set aperture to f/11 and shutter speed to the (reciprocal of the) ISO setting.

With ISO 100, set the aperture to f/11 and the shutter speed to 1/100 or 1/125 second.
With ISO 200, aperture at f/11 set the shutter speed to 1/200 or 1/250.
With ISO 400, aperture at f/11, set the shutter speed to 1/400 or 1/500.

bwana Loc: Bergen, Alberta, Canada

Or somewhere close to this...

bwa

Sidwalkastronomy Loc: New Jersey Shore

The moon is like daylight exposure because that's what it is. The light from sun just like sun shinning on a land Subject. Bracket also