CatMarley wrote:
Maybe I am being too simplistic, but the sensor of a 24MP camera creates an image 6000 x 4000 pixels. In printing, if every pixel is converted to an ink dot, at 240 dpi, the 24mp image can be printed at 6000/240 dpi registering every pixel - a print 25 inches wide. A 36mp sensor gives an image about 7350 pixels wide which at 240 dpi will give a print 30 inches wide.
But you can't actually print the original 6000x4000 pixel image at 240 PPI, because there are no printers with a native rate of 240 Pixels Per Inch. Canon and HP print at 300 PPI and Epson prints at 360. So to print an image that has 6000 pixels across at 25 inches wide the image has to be resampled, interpolating 360 pixels for each original 240 pixels to get a 9000x6000 image. The resampling has a negative effect on how the fine detail of an image is seen when viewed because the size of the print was increased, but there isn't more actual detail (hence in effect the "resolution" of the image is reduced).
To compare print sizes as a measure of resolution you have to specify the printer, and stick with the actual PPI rate the printer uses. Resampling interferes with easy comparisons.
CatMarley wrote:
However the pixel definition will depend on other factors - the lens and whether there is a low pass filter on the sensor. The dot accuracy will depend on the printer's ink nozzle. There are too many variables here to say whether the camera or the lens will dominate the result.
Yes there are many things that affect resolution. But you always have to start with the sensor's pixel rate, because that sets the
maximum resolution that can be captured. No matter how sharp the lens, how close you get to the subject nor how much detail there is in the scene, the maximum resolution is limited to what the sensor can record. (See the
Nyquist-Shannon Sampling Theorum.)
Hence the D7200 camera with a limit of 127 lp/mm, at the same distance and using the same lens, can record finer detail, if it exists in the scene, than can a D810 camera that has a limit of 102 lp/mm. In practice what we do is
change the spatial frequency of the image detail that is projected onto the sensor. Getting closer to a picket fence makes the pickets larger and farther apart. That equals lower spatial frequency and requires lower resolution to capture accurately. Using a longer focal length lens has the exact same effect.
Consider that a Nikon D4 has an even lower resolution sensor than the D810. The D4 can only record 68 lp/mm. Hence if we have a 50mm lens and take a picture of the white picket fence around a house from a distance of 2000 feet, none of those cameras will be able to capture the detail in the pickets which will be just a white blur. If we move up closer there is some point at which the D7200 image will just barely show the detail of the pickets, but the others won't. If we get up very close, even the D4 will clearly show the individual pickets.
We could move to the distance where the D7200 is just showing detail with a 50mm lens, and then put a 600mm lens on the D4 and get better detail in that fence than the D7200 with a 50mm lens can capture. But with both distance and focal length what we have done is not really increase the resolution of the data recorded, but rather we have reduced the spatial frequency to where it is low enough to be recorded by each of those sensors. The higher the resolution of the sensor the less change to the spatial frequency required.
That is why the D7200 is the choice if you are "focal length limited" and can't move closer to a subject. That is commonly the case for bird photographers, or even those shooting other kinds of wildlife. A D810 with lots of pixels for large prints is nice, but you can't print fine detail that was not captured by the sensor in the first place.