Missing money
Feb 5, 2016 12:17:26 #
Manny Jay
Loc: Colorado
OK youse guys, this one is as old as the hills. Figure it out!
Three men on a business trip decided to share a hotel room. They found a crappy hotel for $30.00 per room. They each pitched in $10.00 and paid the manager and went on up to their room.
The manager realized there was no hot water in that room and the price should have been $25.00, so he called the helper and told him to return $5.00 dollars to the men. The helper thought about it and figured it would be hard to divide the five three ways, so he put two dollars in his pocket and returned one dollar to each man. Thus, the men each paid $9.00 for the room.
Three times nine is 27, plus the two dollars the helper has in his pocket, equals 29!
Where is the other dollar?
Three men on a business trip decided to share a hotel room. They found a crappy hotel for $30.00 per room. They each pitched in $10.00 and paid the manager and went on up to their room.
The manager realized there was no hot water in that room and the price should have been $25.00, so he called the helper and told him to return $5.00 dollars to the men. The helper thought about it and figured it would be hard to divide the five three ways, so he put two dollars in his pocket and returned one dollar to each man. Thus, the men each paid $9.00 for the room.
Three times nine is 27, plus the two dollars the helper has in his pocket, equals 29!
Where is the other dollar?
Feb 5, 2016 12:45:17 #
You must be hiding in the north east If you said youal your are a southerner if you said youens you are from Penn
Feb 5, 2016 13:04:34 #
Feb 5, 2016 14:52:56 #
Feb 6, 2016 07:05:57 #
Quite easy. Each man paid $9, total $27, less the $2 taken by the helper left $25 for the owner!
Feb 6, 2016 14:24:33 #
Feb 6, 2016 14:46:55 #
When the helper returned $1 to each, leaving $2, it meant they paid $9.66666666 each for the room.
Feb 6, 2016 16:35:47 #
pisherofmen
Loc: New Port Richey Florida
Each man actually paid $9.333 for the room dividing the $25.00 three ways.
Feb 6, 2016 21:15:41 #
Feb 7, 2016 15:25:38 #
Bindlestiff
Loc: Brookfield, WI
The following night two men registered and once again the clerk made the same mistake and charged them $30. To correct the error he sent the bellboy up with five singles. Knowing that they couldn't divide that evenly he gave each a dollar and kept three. So they each paid $14.
2 * 14 = 28 plus the three the bellboy kept is 31 so we are now all even.
2 * 14 = 28 plus the three the bellboy kept is 31 so we are now all even.
Feb 7, 2016 17:18:25 #
tairving
Loc: Magnolia, Texas USA
So now a bit of algebra for you:
A=1 and B=1
Thus,
A = B
Multiplying both sides by A,
A^2 = AB
Subtracting B^2 from both sides,
A^2 B^2 = AB - B^2
Factoring,
(A+B)*(A-B) = B*(A-B)
Canceling out the common factor (A-B),
A+B = B
And, since A=1 and B=1,
2 = 1
How can this be?
A=1 and B=1
Thus,
A = B
Multiplying both sides by A,
A^2 = AB
Subtracting B^2 from both sides,
A^2 B^2 = AB - B^2
Factoring,
(A+B)*(A-B) = B*(A-B)
Canceling out the common factor (A-B),
A+B = B
And, since A=1 and B=1,
2 = 1
How can this be?
Feb 8, 2016 10:54:50 #
tairving
Loc: Magnolia, Texas USA
Apologies, it appears that I killed off this message thread. It is an old math joke.
The error lies in the step "Cancelling out the common factor". The problem is that the common factor (A-B) is equal to zero and in "cancelling it out", we divided by zero. That, dividing by zero, is not allowed in mathematics and invalidates everything that follows.
The error lies in the step "Cancelling out the common factor". The problem is that the common factor (A-B) is equal to zero and in "cancelling it out", we divided by zero. That, dividing by zero, is not allowed in mathematics and invalidates everything that follows.
tairving wrote:
So now a bit of algebra for you:
A=1 and B=1
Thus,
A = B
Multiplying both sides by A,
A^2 = AB
Subtracting B^2 from both sides,
A^2 B^2 = AB - B^2
Factoring,
(A+B)*(A-B) = B*(A-B)
Canceling out the common factor (A-B),
A+B = B
And, since A=1 and B=1,
2 = 1
How can this be?
A=1 and B=1
Thus,
A = B
Multiplying both sides by A,
A^2 = AB
Subtracting B^2 from both sides,
A^2 B^2 = AB - B^2
Factoring,
(A+B)*(A-B) = B*(A-B)
Canceling out the common factor (A-B),
A+B = B
And, since A=1 and B=1,
2 = 1
How can this be?
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