I've just read an article on Tom's Guide (
www.tomsguide.com) about the size of prints from digital cameras and the correlation between the two. The article went as follows;
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For most people, the highest resolution files they will need will be for the occasional print or photo book. Hereâs how you calculate the number of megapixels youâll need for a printed photograph:
Determine the physical size of your print, such as 4 x 6 inches, 8 x 10 inches, etc. Then, multiply the width by 300, and the height by 300, which will give you the size in terms of pixels. (300 ppi â pixels per inch â is recommended for good-quality prints.) Therefore, an 8 x 10 inch print would be 2,400 x 3,000 pixels.
Multiply the width (in pixels) by the height (in pixels). So for that 8 x 10 inch print, it would be 2400 x 3000, which equals 7.2 million pixels.
Divide the result from step 2 by 1 million, and you have the number of megapixels you need to make a good print. In this case, the minimum resolution youâll want your camera to have is 7.2 megapixels.
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Using the above calculation I figure that a 9" x 9" print will come out at around 7.29MP. I've chosen a square one to make the comparison below a bit easier.
Working backwards from this, my camera, a Canon 760D, has 24.2 MP; the square root of 24.2 million is (roughly) 4920. Divide this number by 300 and I end up with a maximum print size of around 16.4" x 16.4".
This seems a bit small but it won't be the first time my calculations have gone awry.
Question: Does that sound about right?
I have no desire, or intent to print anything bigger, I'm just curious and continuing my learning process.
Thanks.
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