randave2001 wrote:
OK, I changed my mind. Here is what I come up with:
2 shoes = 10 therefore 1 shoe =5
Boy = 5
2 bouquets = 4 therefore 1 bouquet = 2
Final formula is:
1 shoe + (boy holding 2 bouquets and wearing 2 shoes) X 1 bouquet which would numerically be 5 + (5+4+10) X 2 or 5+19X2. Using the MDAS method of solving that would then be 5+38=43 (final answer).
I use BODMAS, acronym for Bracket, Order, Division, Multiplication, Addition and Subtraction. In certain regions, PEMDAS (Parentheses, Exponents, Multiplication, Division, Addition and Subtraction)
I got 60, so who is right? shoes are 10 plus person 5 = 15 times cone 4 =60 for me.
I missed that there was only one shoe in the problem, not two
Jeff Gordon wrote:
Depends if you do the multiplication first or last. First I get 43, last I get 48,
I knew I shouldn't have done this when I was tired. I forgot to do the multiplication on both sides of the X sign before adding the first part.
FINAL ANSWER: 23
I got 117 1/2...how did all of you get it so wrong!!
I came up with 40.
10+ 10+10=30
5+5+10=20
4+4+5=13
5+5= 10
10X4=40
Are we ever going to find out the answer?
Shoeless_Photographer wrote:
I knew I shouldn't have done this when I was tired. I forgot to do the multiplication on both sides of the X sign before adding the first part.
FINAL ANSWER: 23
Ah, crap! I should know better. These things are, like the OP said, all about observation. Turns out the boy is wearing those same red shoes in the last one. Missed that 'cause I normally don't wear ANY shoes. LOL
FINAL FINAL ANSWER: 43
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